\(\int \frac {A+B x^2}{(e x)^{5/2} (a+b x^2)^{5/2}} \, dx\) [821]

Optimal result

Integrand size = 26, antiderivative size = 213 \[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=-\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}}-\frac {(3 A b-a B) \sqrt {e x}}{3 a^2 e^3 \left (a+b x^2\right )^{3/2}}-\frac {5 (3 A b-a B) \sqrt {e x}}{6 a^3 e^3 \sqrt {a+b x^2}}-\frac {5 (3 A b-a B) \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right ),\frac {1}{2}\right )}{12 a^{13/4} \sqrt [4]{b} e^{5/2} \sqrt {a+b x^2}} \]

[Out]

-2/3*A/a/e/(e*x)^(3/2)/(b*x^2+a)^(3/2)-1/3*(3*A*b-B*a)*(e*x)^(1/2)/a^2/e^3/(b*x^2+a)^(3/2)-5/6*(3*A*b-B*a)*(e*
x)^(1/2)/a^3/e^3/(b*x^2+a)^(1/2)-5/12*(3*A*b-B*a)*(cos(2*arctan(b^(1/4)*(e*x)^(1/2)/a^(1/4)/e^(1/2)))^2)^(1/2)
/cos(2*arctan(b^(1/4)*(e*x)^(1/2)/a^(1/4)/e^(1/2)))*EllipticF(sin(2*arctan(b^(1/4)*(e*x)^(1/2)/a^(1/4)/e^(1/2)
)),1/2*2^(1/2))*(a^(1/2)+x*b^(1/2))*((b*x^2+a)/(a^(1/2)+x*b^(1/2))^2)^(1/2)/a^(13/4)/b^(1/4)/e^(5/2)/(b*x^2+a)
^(1/2)

Rubi [A] (verified)

Time = 0.12 (sec) , antiderivative size = 213, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {464, 296, 335, 226} \[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=-\frac {5 \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} (3 A b-a B) \operatorname {EllipticF}\left (2 \arctan \left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right ),\frac {1}{2}\right )}{12 a^{13/4} \sqrt [4]{b} e^{5/2} \sqrt {a+b x^2}}-\frac {5 \sqrt {e x} (3 A b-a B)}{6 a^3 e^3 \sqrt {a+b x^2}}-\frac {\sqrt {e x} (3 A b-a B)}{3 a^2 e^3 \left (a+b x^2\right )^{3/2}}-\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}} \]

[In]

Int[(A + B*x^2)/((e*x)^(5/2)*(a + b*x^2)^(5/2)),x]

[Out]

(-2*A)/(3*a*e*(e*x)^(3/2)*(a + b*x^2)^(3/2)) - ((3*A*b - a*B)*Sqrt[e*x])/(3*a^2*e^3*(a + b*x^2)^(3/2)) - (5*(3
*A*b - a*B)*Sqrt[e*x])/(6*a^3*e^3*Sqrt[a + b*x^2]) - (5*(3*A*b - a*B)*(Sqrt[a] + Sqrt[b]*x)*Sqrt[(a + b*x^2)/(
Sqrt[a] + Sqrt[b]*x)^2]*EllipticF[2*ArcTan[(b^(1/4)*Sqrt[e*x])/(a^(1/4)*Sqrt[e])], 1/2])/(12*a^(13/4)*b^(1/4)*
e^(5/2)*Sqrt[a + b*x^2])

Rule 226

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[(1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(
1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))*EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 296

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-(c*x)^(m + 1))*((a + b*x^n)^(p + 1)/
(a*c*n*(p + 1))), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; Free
Q[{a, b, c, m}, x] && IGtQ[n, 0] && LtQ[p, -1] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 335

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 464

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[c*(e*x)^(m +
1)*((a + b*x^n)^(p + 1)/(a*e*(m + 1))), x] + Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(a*e^n*(m + 1)), In
t[(e*x)^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[b*c - a*d, 0] && (IntegerQ[n] ||
GtQ[e, 0]) && ((GtQ[n, 0] && LtQ[m, -1]) || (LtQ[n, 0] && GtQ[m + n, -1])) &&  !ILtQ[p, -1]

Rubi steps \begin{align*} \text {integral}& = -\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}}-\frac {(3 A b-a B) \int \frac {1}{\sqrt {e x} \left (a+b x^2\right )^{5/2}} \, dx}{a e^2} \\ & = -\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}}-\frac {(3 A b-a B) \sqrt {e x}}{3 a^2 e^3 \left (a+b x^2\right )^{3/2}}-\frac {(5 (3 A b-a B)) \int \frac {1}{\sqrt {e x} \left (a+b x^2\right )^{3/2}} \, dx}{6 a^2 e^2} \\ & = -\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}}-\frac {(3 A b-a B) \sqrt {e x}}{3 a^2 e^3 \left (a+b x^2\right )^{3/2}}-\frac {5 (3 A b-a B) \sqrt {e x}}{6 a^3 e^3 \sqrt {a+b x^2}}-\frac {(5 (3 A b-a B)) \int \frac {1}{\sqrt {e x} \sqrt {a+b x^2}} \, dx}{12 a^3 e^2} \\ & = -\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}}-\frac {(3 A b-a B) \sqrt {e x}}{3 a^2 e^3 \left (a+b x^2\right )^{3/2}}-\frac {5 (3 A b-a B) \sqrt {e x}}{6 a^3 e^3 \sqrt {a+b x^2}}-\frac {(5 (3 A b-a B)) \text {Subst}\left (\int \frac {1}{\sqrt {a+\frac {b x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{6 a^3 e^3} \\ & = -\frac {2 A}{3 a e (e x)^{3/2} \left (a+b x^2\right )^{3/2}}-\frac {(3 A b-a B) \sqrt {e x}}{3 a^2 e^3 \left (a+b x^2\right )^{3/2}}-\frac {5 (3 A b-a B) \sqrt {e x}}{6 a^3 e^3 \sqrt {a+b x^2}}-\frac {5 (3 A b-a B) \left (\sqrt {a}+\sqrt {b} x\right ) \sqrt {\frac {a+b x^2}{\left (\sqrt {a}+\sqrt {b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{b} \sqrt {e x}}{\sqrt [4]{a} \sqrt {e}}\right )|\frac {1}{2}\right )}{12 a^{13/4} \sqrt [4]{b} e^{5/2} \sqrt {a+b x^2}} \\ \end{align*}

Mathematica [C] (verified)

Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.

Time = 10.08 (sec) , antiderivative size = 120, normalized size of antiderivative = 0.56 \[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=\frac {x \left (-15 A b^2 x^4+a^2 \left (-4 A+7 B x^2\right )+a \left (-21 A b x^2+5 b B x^4\right )+5 (-3 A b+a B) x^2 \left (a+b x^2\right ) \sqrt {1+\frac {b x^2}{a}} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},\frac {1}{2},\frac {5}{4},-\frac {b x^2}{a}\right )\right )}{6 a^3 (e x)^{5/2} \left (a+b x^2\right )^{3/2}} \]

[In]

Integrate[(A + B*x^2)/((e*x)^(5/2)*(a + b*x^2)^(5/2)),x]

[Out]

(x*(-15*A*b^2*x^4 + a^2*(-4*A + 7*B*x^2) + a*(-21*A*b*x^2 + 5*b*B*x^4) + 5*(-3*A*b + a*B)*x^2*(a + b*x^2)*Sqrt
[1 + (b*x^2)/a]*Hypergeometric2F1[1/4, 1/2, 5/4, -((b*x^2)/a)]))/(6*a^3*(e*x)^(5/2)*(a + b*x^2)^(3/2))

Maple [A] (verified)

Time = 4.19 (sec) , antiderivative size = 267, normalized size of antiderivative = 1.25

method	result	size
elliptic	\(\frac {\sqrt {\left (b \,x^{2}+a \right ) e x}\, \left (-\frac {\left (A b -B a \right ) \sqrt {b e \,x^{3}+a e x}}{3 a^{2} e^{3} b^{2} \left (x^{2}+\frac {a}{b}\right )^{2}}-\frac {x \left (11 A b -5 B a \right )}{6 e^{2} a^{3} \sqrt {\left (x^{2}+\frac {a}{b}\right ) b e x}}-\frac {2 A \sqrt {b e \,x^{3}+a e x}}{3 a^{3} e^{3} x^{2}}+\frac {\left (-\frac {11 A b -5 B a}{12 a^{3} e^{2}}-\frac {b A}{3 a^{3} e^{2}}\right ) \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{b \sqrt {b e \,x^{3}+a e x}}\right )}{\sqrt {e x}\, \sqrt {b \,x^{2}+a}}\)	\(267\)
default	\(-\frac {15 A \sqrt {2}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-a b}\, b^{2} x^{3}-5 B \sqrt {2}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-a b}\, a b \,x^{3}+15 A \sqrt {2}\, \sqrt {-a b}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) a b x -5 B \sqrt {2}\, \sqrt {-a b}\, \sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {\frac {-b x +\sqrt {-a b}}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {b x +\sqrt {-a b}}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right ) a^{2} x +30 A \,b^{3} x^{4}-10 B a \,b^{2} x^{4}+42 a A \,b^{2} x^{2}-14 B \,a^{2} b \,x^{2}+8 a^{2} b A}{12 x \,e^{2} \sqrt {e x}\, a^{3} b \left (b \,x^{2}+a \right )^{\frac {3}{2}}}\)	\(446\)
risch	\(-\frac {2 A \sqrt {b \,x^{2}+a}}{3 a^{3} x \,e^{2} \sqrt {e x}}-\frac {\left (\frac {A \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{\sqrt {b e \,x^{3}+a e x}}+3 a b A \left (\frac {x}{a \sqrt {\left (x^{2}+\frac {a}{b}\right ) b e x}}+\frac {\sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{2 a b \sqrt {b e \,x^{3}+a e x}}\right )+3 a^{2} \left (A b -B a \right ) \left (\frac {\sqrt {b e \,x^{3}+a e x}}{3 a e \,b^{2} \left (x^{2}+\frac {a}{b}\right )^{2}}+\frac {5 x}{6 a^{2} \sqrt {\left (x^{2}+\frac {a}{b}\right ) b e x}}+\frac {5 \sqrt {-a b}\, \sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}\, \sqrt {-\frac {x b}{\sqrt {-a b}}}\, F\left (\sqrt {\frac {\left (x +\frac {\sqrt {-a b}}{b}\right ) b}{\sqrt {-a b}}}, \frac {\sqrt {2}}{2}\right )}{12 a^{2} b \sqrt {b e \,x^{3}+a e x}}\right )\right ) \sqrt {\left (b \,x^{2}+a \right ) e x}}{3 a^{3} e^{2} \sqrt {e x}\, \sqrt {b \,x^{2}+a}}\)	\(492\)

[In]

int((B*x^2+A)/(e*x)^(5/2)/(b*x^2+a)^(5/2),x,method=_RETURNVERBOSE)

[Out]

((b*x^2+a)*e*x)^(1/2)/(e*x)^(1/2)/(b*x^2+a)^(1/2)*(-1/3/a^2/e^3/b^2*(A*b-B*a)*(b*e*x^3+a*e*x)^(1/2)/(x^2+a/b)^
2-1/6/e^2*x/a^3*(11*A*b-5*B*a)/((x^2+a/b)*b*e*x)^(1/2)-2/3/a^3/e^3*A*(b*e*x^3+a*e*x)^(1/2)/x^2+(-1/12/a^3*(11*
A*b-5*B*a)/e^2-1/3*b/a^3/e^2*A)*(-a*b)^(1/2)/b*((x+(-a*b)^(1/2)/b)/(-a*b)^(1/2)*b)^(1/2)*(-2*(x-(-a*b)^(1/2)/b
)/(-a*b)^(1/2)*b)^(1/2)*(-x/(-a*b)^(1/2)*b)^(1/2)/(b*e*x^3+a*e*x)^(1/2)*EllipticF(((x+(-a*b)^(1/2)/b)/(-a*b)^(
1/2)*b)^(1/2),1/2*2^(1/2)))

Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.08 (sec) , antiderivative size = 174, normalized size of antiderivative = 0.82 \[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=\frac {5 \, {\left ({\left (B a b^{2} - 3 \, A b^{3}\right )} x^{6} + 2 \, {\left (B a^{2} b - 3 \, A a b^{2}\right )} x^{4} + {\left (B a^{3} - 3 \, A a^{2} b\right )} x^{2}\right )} \sqrt {b e} {\rm weierstrassPInverse}\left (-\frac {4 \, a}{b}, 0, x\right ) + {\left (5 \, {\left (B a b^{2} - 3 \, A b^{3}\right )} x^{4} - 4 \, A a^{2} b + 7 \, {\left (B a^{2} b - 3 \, A a b^{2}\right )} x^{2}\right )} \sqrt {b x^{2} + a} \sqrt {e x}}{6 \, {\left (a^{3} b^{3} e^{3} x^{6} + 2 \, a^{4} b^{2} e^{3} x^{4} + a^{5} b e^{3} x^{2}\right )}} \]

[In]

integrate((B*x^2+A)/(e*x)^(5/2)/(b*x^2+a)^(5/2),x, algorithm="fricas")

[Out]

1/6*(5*((B*a*b^2 - 3*A*b^3)*x^6 + 2*(B*a^2*b - 3*A*a*b^2)*x^4 + (B*a^3 - 3*A*a^2*b)*x^2)*sqrt(b*e)*weierstrass
PInverse(-4*a/b, 0, x) + (5*(B*a*b^2 - 3*A*b^3)*x^4 - 4*A*a^2*b + 7*(B*a^2*b - 3*A*a*b^2)*x^2)*sqrt(b*x^2 + a)
*sqrt(e*x))/(a^3*b^3*e^3*x^6 + 2*a^4*b^2*e^3*x^4 + a^5*b*e^3*x^2)

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 128.92 (sec) , antiderivative size = 97, normalized size of antiderivative = 0.46 \[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=\frac {A \Gamma \left (- \frac {3}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {3}{4}, \frac {5}{2} \\ \frac {1}{4} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {5}{2}} e^{\frac {5}{2}} x^{\frac {3}{2}} \Gamma \left (\frac {1}{4}\right )} + \frac {B \sqrt {x} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} \frac {1}{4}, \frac {5}{2} \\ \frac {5}{4} \end {matrix}\middle | {\frac {b x^{2} e^{i \pi }}{a}} \right )}}{2 a^{\frac {5}{2}} e^{\frac {5}{2}} \Gamma \left (\frac {5}{4}\right )} \]

[In]

integrate((B*x**2+A)/(e*x)**(5/2)/(b*x**2+a)**(5/2),x)

[Out]

A*gamma(-3/4)*hyper((-3/4, 5/2), (1/4,), b*x**2*exp_polar(I*pi)/a)/(2*a**(5/2)*e**(5/2)*x**(3/2)*gamma(1/4)) +
B*sqrt(x)*gamma(1/4)*hyper((1/4, 5/2), (5/4,), b*x**2*exp_polar(I*pi)/a)/(2*a**(5/2)*e**(5/2)*gamma(5/4))

Maxima [F]

\[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=\int { \frac {B x^{2} + A}{{\left (b x^{2} + a\right )}^{\frac {5}{2}} \left (e x\right )^{\frac {5}{2}}} \,d x } \]

[In]

integrate((B*x^2+A)/(e*x)^(5/2)/(b*x^2+a)^(5/2),x, algorithm="maxima")

[Out]

integrate((B*x^2 + A)/((b*x^2 + a)^(5/2)*(e*x)^(5/2)), x)

Giac [F]

\[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=\int { \frac {B x^{2} + A}{{\left (b x^{2} + a\right )}^{\frac {5}{2}} \left (e x\right )^{\frac {5}{2}}} \,d x } \]

[In]

integrate((B*x^2+A)/(e*x)^(5/2)/(b*x^2+a)^(5/2),x, algorithm="giac")

[Out]

integrate((B*x^2 + A)/((b*x^2 + a)^(5/2)*(e*x)^(5/2)), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {A+B x^2}{(e x)^{5/2} \left (a+b x^2\right )^{5/2}} \, dx=\int \frac {B\,x^2+A}{{\left (e\,x\right )}^{5/2}\,{\left (b\,x^2+a\right )}^{5/2}} \,d x \]

[In]

int((A + B*x^2)/((e*x)^(5/2)*(a + b*x^2)^(5/2)),x)

[Out]

int((A + B*x^2)/((e*x)^(5/2)*(a + b*x^2)^(5/2)), x)